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A coin has two sides. One side has the number 1 on it and the other side has the number 2 on it. If the coin is flipped three times what is the probability that the sum of the numbers on the landing side of the coin will be greater than 4?
Correct Answer: D
Use the multiplication rule of probabilities
  1. One approach to solve the problem is to list the different possibilities for a toss of coin three times. Because there are two outcomes and the coin is tossed three times, the table will have 2*2*2 or 8 rows.
  2. Next add the resulting rows together to find the sum (the fourth column in the table below).
    Toss 1 Toss 2 Toss 3 Sum
    1 1 1 3
    1 1 2 4
    1 2 1 4
    1 2 2 5
    2 1 1 4
    2 1 2 5
    2 2 1 5
    2 2 2 6
  3. From the table we see that there are 4 situations where the sum of the tosses will be greater than 4. And there are 8 possible combinations resulting in a probability of
  4. 4/8 or a probability of1/2. SO the correct answer is D.

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